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Question:

Question 1: If A, B and C are interior angles of a triangle ABC, then sin{(B + C)/2} =

Answer:

Given, A, B and C are interior angles of a triangle ABC.

=> A + B + C = 180

=> (A + B + C)/2 = 180/2

=> (A + B + C)/2 = 90

=> A/2 + (B + C)/2 = 90

=> (B + C)/2 = 90 - A/2

Now, sin {(B + C)/2} = sin (90 - A/2) = cos A/2

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